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4p^2-2p-72=0
a = 4; b = -2; c = -72;
Δ = b2-4ac
Δ = -22-4·4·(-72)
Δ = 1156
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1156}=34$$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-34}{2*4}=\frac{-32}{8} =-4 $$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+34}{2*4}=\frac{36}{8} =4+1/2 $
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